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Markup or Margin
Selling and Pricing
Contents
Half the art of selling, is the art of pricing. Know the market and discern the customer.
These are things of intuition and experience, what price is fair for this customer, and what price will the market bear ?
In order to do this efficiently, you need to be confident that the price you're selling for is profitable. Not only that, you must be able to quickly navigate through the forest of supplier discounts, list prices, VAT, and acceptable margins.
Two terms used when discussing prices are markup and margin. They are different ways of calculating profit, and the difference can be confusing.
This article explains the difference between markup and margin, and equips you to easily calculate prices and profits in whatever situation you find yourself.
Many retail establishments do their calculations based on markups. This is not the same thing as margin. This is often a source of confusion - but only because percentages are difficult until you understand them.
Margin
The percentage margin is the percentage of the final selling price that is profit.
Markup
A markup is what percentage of the cost price do you add on to get the selling price.
These are different, a selling price with a margin of 25%  results in more profit than a selling price with a markup of 25%.
In a merchant situation it is probably better to work with margins. This means you can know what percentage of our total income is profit.
Note
Obviously profits calculated in this way are gross profits.
Your overheads (like rates, fixed costs, corporation tax, wages, etc) still need to be taken off before you can know your nett profit.
This is why you'll need to establish policies with minimum acceptable margins.
With margins, a 50% margin means that half the selling price is profit. In markups, that is a 100% markup (you have added 100% of the cost price to make the selling price). With margins, a 100% margin is only possible if the cost price is zero.
To understand why margins are higher, imagine an item that costs fifty pounds. If you sell it with a margin of 50% - that means fifty percent of the selling price should be profit. If you sell it at 100 pounds, half the selling price is profit - margin 50%.
If you sell the same item (cost fifty pounds) with a markup of fifty percent, you add fifty percent of the cost price. Fifty percent of the cost price is twenty-five pounds. This makes the total selling price seventy-five pounds.
A fifty percent margin is higher than a fifty percent markup.
You will often have to calculate margins. Either to work out a selling price from a cost price, or to work out what margin a certain selling price would result in.
The full formula for working out a selling price from a cost price and a certain margin is :
selling = cost/((100-margin)/100)
Thankfully there is a quicker way to work it out.
For a five percent margin, divide the cost price by 0.95.
For a ten percent margin, divide the cost price by 0.9.
For a fifteen percent margin, divide the cost price by 0.85.
For a twenty percent margin, divide the cost price by 0.8.
For a twenty-five percent margin, divide the cost price by 0.75.
For a thirty percent margin, divide the cost price by 0.7.
Hopefully you can see the pattern.
Sometimes you will have a cost and selling price, and need to know what margin that results in. The formula is :
margin = (1 - (cost/selling))x100
You can work it back from the examples given in Selling Price from Cost Price.
If cost/selling is 0.95, the margin is five percent.
If cost/selling is 0.9, the margin is ten percent.
If cost/selling is 0.85, the margin is fifteen percent.
If cost/selling is 0.8, the margin is twenty percent.
etc...
Many suppliers prefer to quote list prices less a discount. In these circumstances it is useful to be able to quote customers a discount off list. They love the idea that they are getting a discount.
To work out the nett. cost price (what we pay) from a list less discount, use the following formula :
cost = list * ((100 - discount)/100)
Working out what discount to quote customers, whilst still maintaining an acceptable margin, can be fiddly.
You can work it out as follows. final discount is the discount to offer the customer, supplier discount is the percentage off list price you have been offered, list is the list price and margin is the margin you want to make as a percentage.
cost = list * ((100 - supplier discount)/100)
selling = cost/((100-margin)/100)
final discount = (1 - selling/list) * 100
It can actually be easier to guess a few times though. Work out the cost price. Then work out the selling price if you offer (for example) forty percent off list - and see what margin that leaves you with. If it is too little, try reducing the discount you offer - or vice versa.
It is normal for trade outlets quote prices exclusive of VAT.
To add VAT to a price, multiply by 1.175.
If you have a price including VAT and need to work out the ex-VAT price, divide by 1.175.
There are one or two items which should be sold without VAT (like safety boots). These ought to be saleable with a zero VAT rate - sometimes your point of sale system will mean that's not possible. If a customer picks up on this, you are probably obliged to sell without charging them VAT.
Exports
You may have the situation where customers are buying the goods for export, and you are shipping the goods to the docks (or even arranging delivery abroad).
In these circumstances it is possible that VAT is not chargeable. This is also complicated - and you need to check with customs for the correct procedure.
Also see: Partner Directory.

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What Is the Difference Between Margin and Markup?

, eHow Contributor
Description: What Is the Difference Between Margin and Markup? thumbnailWhat Is the Difference Between Margin and Markup?
Margin (or gross margin) and markup are two different ways of expressing the difference between the cost of a product and its sale price. However, margin and markup are computed differently and are used for different purposes, depending on which is more suitable. Most small businesses use markup formulas, but many neglect margin. That's a mistake, according to business consultants, since using margin as a tool for analysis helps improve profitability. It's well worth the time for any businessperson to know the difference between margin and markup and how to use both.

Other People Are Reading

1.   Identification

o    Markup is the amount (usually expressed as a percentage) that is added to the cost of a good to set the selling price. For example, if an item costs $10 and the markup percentage is 50 percent, you add $10 (50 percent) or $5 to get a price of $15. The margin of a good that has a $15 price and a cost of $10 is the price minus the cost (in this example, $5). Express this as margin percentage by dividing the margin by the price and then multiplying by 100. Our $5 margin divided by the $15 price (times 100) yields a margin percentage of 33 percent.

Significance

o    Margin and markup have different uses. Generally, a markup formula is used to set the price of a product. It's a simple and easy way to guide sales personnel and managers. Margin is more useful for analyzing sales and expenses. Typically, you use data from a given period (such as the previous calendar quarter) to determine how much margin is required for existing sales volume to cover added expenses plus an adequate profit. The goal is to use margin analysis to adjust prices and determine what your markup formula should be.
See how a commission tracking system can boost your revenue!

Features

o    The cost of a product is a common factor for both margin and markup. It consists of the purchase price of the item (raw materials) plus labor and may include items like breakage allowance. Cost does not include other expenditures such as rent, administrative salaries and office expenses. A margin analysis takes actual data on costs, sales and expenses and creates a model that allocates the proportion of expenses that the margin must cover. Once you do this analysis, you have the necessary information to effectively set or adjust prices and create a useful markup formula for pricing.

Function

o    It is frequently necessary to convert margin to markup to establish a markup formula. To do this, subtract cost from the sale price to obtain the margin. Then divide margin by cost (multiply by 100 to get the markup percentage). For example, an item with a cost of $10 and a price of $15 has a margin of $15 minus $10, or $5. Divide $5 by cost ($10) and multiply by 100 to get the markup percentage of 50 percent. You don't really need to convert markup to margin; just subtract cost from the price to get the margin. Divide by the sale price and multiply by 100 to find the margin percentage.

Considerations

o    Determining the right markup to set the price of a product is vital. You don't want to underprice or overprice products. Tracking margin on a regular basis enables you to avoid both problems. Using margin to analyze sales and expenses can also help you to identify products that are not "pulling their weight." Another advantage is identifying how much you can offer in coupons and sales to build customer base and sales volume without discounting too deeply.







TURNOVER\

turnover

  

Definitions (3)Save to FavoritesSee Examples

1. Accounting: (1) The annual sales volume net of all discounts and sales taxes.
(2) The number of times an asset (such as cash, inventory, raw materials) is replaced or revolves during an accounting period.
2. Human resource management: The number of employees hired to replace those who left or were fired during a 12 month period.
3. Finance: The volume or value of shares traded on a stock exchange during a day, month, or year.

Usage Examples









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HIRE-PURCHASE SYSTEM (PART I)


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1.0 HIRE-PURCHASE SYSTEM ( PART I )


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Chapter Outline

1.1 Introduction
1.2 Objectives
1.3 Meaning and concept of Hire-purchase System
1.4 Characteristics of Hire-purchase system
1.5 Difference between Hire-purchase system and Instalment payment system
1.6 Accounting entries in the books of Hire-purchaser
1.7 Accounting entries in the books of Hire vendor
1.8 Calculation of Cash Price, if Cash Price is not given
1.9 Calculation of Amount of Interest,if rate of Interest is not given
1.10 Let's Sum up
1.11 Home Assignments
1.12 Further Readings
1.13 Answer to SAQs




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Introduction
By now you must have been familiar to various aspects of Book-keeping and Accountancy. You must have understood the concept of double entry system. Now-a-days the books of accounts are maintained under double entry system by all big business houses and multinationals. You know that the sales is the Key factor of success of business. The profit of a business always depends on the volume of its sales. A big business house can effect sales on cash basis as well as on credit basis. The credit sales are very important and essential for the growth of business. The sale proceeds under such sales are not immediately collected but are collected under certain arrangements such as Hire-purchase system or Instalment payment system or collection after a certain period together with interest on outstanding balances. Hire-purchase system is the most secured and effective tool of collecting the proceeds of a credit sale.



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Learning Objectives
After reading this chapter, you are expected to learn about:
  • identify a hire purchase transaction;
  • record the transaction in the journal of hire-purchaser and hire vendor;
  • prepare necessary accounts in the ledger of hire-purchaser and hire vendor;
  • calculate cash price in a transaction of hire-purchase with and without the help of annuity table; and
  • solve the accounting problems of hire- purchase system and record hire purchase transactions in the books of accounts maintained in “Big Malls”.



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1.3 Meaning and Concept of Hire-purchase system

Hire-puchase system is a special system of purchase and sale of goods. Under this system purchaser pays the price of the goods in instalments. The instalments may be annual, six monthly, quarterly, monthly fortnightly etc. Under this system the goods are delivered to the purchaser at the time of agreement before the payment of instalments but the title on the goods is transferred after the payment of all instalments as per the hire-purchase agreement. The special feature of a hire-purchase transaction is that the payment of every instalment is treated as the payment of hire charges by the purchaser to the hire vendor till the payment of the last instalment.. After the payment of the last instalment, the amount of various instalments paid is appropriated towards the payment of the price of the goods sold and the ownership or the goods is transferred to the purchaser. Thus hire-purchase means a transaction where the goods are sold by vendor to the purchaser under the following conditions :
  • the goods will be delivered to the purchaser at the time of agreement.
  • the purchaser has a right to use the goods delivered.
  • the price of the goods will be paid in instalments.
  • every instalment will be treated to be the hire charges of the goods which is being used by the purchaser.
  • if all instalments are paid as per the terms of agreement , the title of the goods is transferred by vendor to the purchaser.
  • if there is a default in the payment of any of the instalments, the vendor will take away the goods from the possession of the purchaser without refunding him any amount received earlier in the form of various instalments.

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1.4 Characteristics of Hire-purchase system

Before discussing the characteristics of hire-purchase system, we must know what is a hire purchase agreement and what are the contents of a hire-purchase agreement. Hire-purchase agreement means a contract between the hire vendor and the hire purchaser regarding the sale of goods under certain conditions. Usually every hire-purchase agreement shall contain the following terms:
  • the cash price of the goods, cash price means the price at which goods may be purchased against cash payment.
  • the hire-purchase price, hire purchase price means the total amount which is payable by the hire-purchaser under the agreement.
  • the date on which the hire-purchase agreement will commence.
  • the description of the goods that will be delivered to the hire-purchaser at the commencement of the agreement.
  • the number of instalments to be paid by the hire-purchaser along with the amount of each instalment and the date of payment of each instalment.
  • the down payment if any, the down payment means the amount which is required to be paid by hire-purchaser to the hire vendor at the time of commencement of hire-purchase agreement.
  • the rate interest charged by the hire vendor (optional).
Characteristics of Hire-Purchase System
The characteristics of hire-purchase system are as under
  • Hire-purchase is a credit purchase.
  • The price under hire-purchase system is paid in instalments.
  • The goods are delivered in the possession of the purchaser at the time of commencement of the agreement.
  • Hire vendor continues to be the owner of the goods till the payment of last instalment.
  • The hire-purchaser has a right to use the goods as a bailer.
  • The hire-purchaser has a right to terminate the agreement at any time in the capacity of a hirer.
  • The hire-purchaser becomes the owner of the goods after the payment of all instalments as per the agreement.
  • If there is a default in the payment of any instalment, the hire vendor will take away the goods from the possession of the purchaser without refunding him any amount.

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Self-Assessment Questions (SAQs) -1
(1) Define Hire-purchase system in your own words. ( 100 words )









(2) State any FIVE important elements of Hire-purchase agreement.








(3) State whether the following statements are True or False:
(a) The hire vendor has to refund the amount received after repossession of goods due to default in payment by hire-purchaser.
(b) Under hire-purchase system the purchaser becomes the owner of the goods immediately after the down payment.
(c)The last instalment under hire-purchase system comprises cash price only.
(d) Under hire-purchase system the buyer does not charge the depreciation on the asset till he becomes the owner.
(e) Interest is calculated on the hire purchase price at the given rate of interest.


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1.5 Difference between Hire-purchase system and Instalment payment system

Instalment Payment System is system of purchase and sale of goods in which title of goods is immediately transferred to the purchaser at the time of sale of goods and the sale price of the goods is paid in instalments. In the event of default in payment of any instalment, the seller has no right to take back goods from the possession of the purchaser. He can file a suit for the recovery of the outstanding balance of the price of goods sold. The followings are the differences between Hire-purchase system and Instalment payment system:
  • In Hire-purchase system, the transfer of ownership takes place after the payment of all instalments while in case of Instalment payment system, the ownership is transferred immediately at the time of agreement.
  • In Hire-purchase system, the hire-purchase agreement is like a contract of hire though later on it may become a purchase after the payment of last instalment while in Instalment payment system, the agreement is like a contract of credit purchase.
  • In case of default in payment , in Hire-purchase system the vendor has a right to back goods from the possession of the hire-purchaser while in case of Instalment payment system, the vendor has no right to take back the goods from the possession of the purchaser; he can simply sue for the balance due.
  • In Hire-purchase system, if the purchaser sells the goods to a third party before the payment of last instalment, the third party does not get a better title on the goods purchased. But in case of Instalment payment system, the third party gets a better title on the goods purchased.
  • In Hire-purchase system the provisions of the Hire-purchase Act apply to the transaction while in case of Instalment payment system, the provisions of Sale of Goods Act apply to the transaction.
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1.6 Accounting In the books of Hire-purchaser

There are two methods of accounting in the books of Hire-purchaser. Their detailed description is as under:-
Asset Accrual Method:
Under this method it is considered that the hire-purchaser is the owner of the asset up to the value of the cash price paid by him in the from of down payment or the cash price paid included in various instalments. The following journal entries are recorded under this method.
(i)On taking the delivery of asset:
    No entry is recorded.
(ii)On making the down payment (if any)
    Asset A/c  Dr.                    (Amount of down payment)       



    To Cash/Bank A/c.                 
(iii)On becoming the instalment due
     Asset a/c. Dr                            (Balancing figure)



     Intt. A/c. Dr.                           (Amt. of Intt.)



     To Hire-Vendor A/c.                      (Amt. of Instalment)
(iv)On payment of instalment:
    Hire-Vendor A/c Dr.                       (Amt. of Instalment)



    To Cash/Bank A/c.  
(v)On charging the Depreciation:
  Depreciation A/c Dr.                (Amt. of Depreciation)



  To Asset A/c.
(vi)On Transfer of interest and depreciation to P/L A/c:
   P/L A/c.                                    (Total  amt.)



   To Interest A/c                            (Bal. of Intt. A/c.)



   To Depreciation A/c.                       (Bal. of Dep. A/c.)



Under Total Assets Value Method:
Under this method of accounting in the books of hire-purchaser, is done on the assumption that the ownership of the asset is also transferred to the purchaser with the delivery of goods. The following journal entries are recorded under this method.
(i)On taking the delivery of assets at the time of agreement:
  Asset A/c Dr.                               (Cash price of Asset)



  To Hire vendor A/c.                         
(ii)On making the down-payment (if any):
   Hire-Vendor....... A/c. Dr.                (Amount of down payment)



   To Cash/Bank A/c                                
(iii)On becoming the instalment due:
  Interest A/c. Dr.                           (Amount of interest)



  To Hire-Vendor A/c                          
(iv)On payment of instalment:
    Hire-Vendor a/c Dr.                              (Amount of instalment)



    To Cash/Bank A/c                          
(v)On charging the depreciations:
   Depreciation A/c. Dr.                             (Amount of depreciation)



   To Asset A/c.                                     
(vi)On Transfer of interest and depreciation to P/L A/c:
    P/L A/c. Dr.                                      (Total)



    To Interest A/c.                                 (Bal. of Intt. A/c.)



    To Depreciation A/c.                              (Bal. of Dep. A/c.)

Posting in Ledger Accounts: After passing journal entries under any of the methods discussed above, the following ledger accounts are opened in the ledger and the postings are made accordingly.
(i) Asset A/c. (e.g. Trucks A/c, Machinery A/c. etc.)
(ii) Vendor's A/c.
(iii) Interest A/c.
(iv) Depreciation A/c.
Note: Before recording the entries the amounts of interest and depreciation will be calculated in two separate tables showing the calculations of interest and depreciation.
Calculation of Interest
The total payment made under hire-purchase system is more than cash price. In fact, this excess of payment over the cash price is interest. It is very essential to calculate interest because the amount paid for interest is charged to revenue and the asset is capitalized at cash price. Thus normally all instalments will include a part of cash price and a part of interest on the outstanding balance. However the amount paid at the time of agreement (down payment) will not include any interest. The calculation of interest is made under two conditions:
(a) When interest is included in amount of instalment: Where the hire-purchase price i.e. payment made in the form of down payment and all instalments is more than the cash price, it is regarded that the interest is included in instalments. It is explained in the following example.
Worked out Example-1 (Calculation of Interest)
On Ist April,2005 Mr. X purchased from M/s Y & Co. one 'Motor Truck' under hire-purchase system, Rs. 5,000 being paid on delivery and the balance in five annual instalments of Rs. 7,500 each payable on 31st March each year. The cash price of the motor truck is Rs. 37,500 and vendors charge interest at the rate of 5 per cent per annum on yearly balances. Find out the amounts of principal and interest included in each instalment.
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(b) When interest is not included in instalments: Where the total amount paid in the form of down payment and all instalments is exactly equal to the cash price, it is regarded that the interest is not included in instalments. It means that interest is payable in addition to the agreed amount of instalment. It is explained in the following example.
Workedout Example-2 (Calculation of Interest): On April 1,2005, A Transport Company purchased a Motor Lorry from Motor Supply Co. Ltd. on hire-purchase basis, the cash price being Rs. 60,000. Rs. 15,000 on signing of the contract and balance in three annual instalments of Rs. 15,000 each on 31st March every year. In addition to it, interest at 5 per cent per annum was also payable to vendors on outstanding balances.
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1.7 Accounting in the books of Hire-vendor

Hire Vendor: There is only one method of recording the entries in the books of hire-vendor. Irrespective of the fact whether the entries in the books of hire-purchaser are passed under the Asset Accrual Method or under the Total asset value Method.But the accounting entries in the books of hire-vendor are always passed under the total Asset Method. These entries are as under:-
(i)On delivery of goods to the hire-purchaser at the time of agreement:
  Hire – purchaser A/c Dr.                    Cash Price



  To Hire – Sales A/c.
(ii)On receipt of cash at the time of agreement (down payment), if any:
 Cash/Bank A/c. Dr.                           (Amt. of down payment)



 To Hire-Purchaser                            
(iii)On interest being due:
 Hire – Purchaser A/c Dr.                     Amt. of Interest



 To Interest A/c.                             
(iv)On receipt of instalment:
 Cash/bank A/c.                               (Amt. of Instalment)



 To Hire – Purchaser                          
(v)On Transfer of Balance of Hire-Sales A/c. to Trading A/c. (at the end of first year only):
  Hire – Sales A/c Dr.                        Cash Price



  To Trading A/c.
(vi)On Transfer of amount of interest to P/L A/c:
   Interest A/c. Dr.                          (Balance of Intt. A/c.)



   To P/L A/c.                                
Note: In solving a numerical problem, before recording the entries, the amount of interest included in various instalments will be separately calculated as already explained.
Posting in Ledger Accounts:
After passing entries in the journall of hire – vendor the following accounts will be opened in the ledger of hire – vendor and the postings will be made accordingly.
  • (i) Hire – Purchaser A/c.
  • (ii) Hire – Sales A/c. (only in first year)
  • (iii) Interest A/c.

Calculate the amount of annual instalment, and show the Journal entries and necessary ledger accounts in the books of Moti Ltd. for three years. The present value of Annuity of Rupees one for three years at 5% is 2.72325.
Worked out examples-3:
On 1st April,2005 X Company Ltd. purchased a machine from Y Machines Ltd. on hire-purchase basis, the cash price being Rs. 55,850 Rs. 15,000 was paid on the signing of the contract and the balance in three annual instalments of Rs. 15,000 each on 31st March each year. Interest is charged at 5% per annum. Depreciation was written off at rate of 10% per annum on the diminishing balance system.
Give journal entries in the books of X Company Ltd. whose accounting year ends on 31st March each year, under Asset Accrual Method.

Solution:


(a) under Asset Accrual Method
Journal Entries in the Books of X Co. Ltd.
Date
Particulars
LF
Dr.(Rs.)
Cr.(Rs.)
2005
April 1
Machinery A/c …………….Dr.
To Bank A/c
(Being down payment made at the time of delivery)

15,000

15,000
2006
March 31
Machinery A/c ……………………………………...Dr.
Interest A/c ....................Dr.
To Y Machine Ltd.
(Being the first instalment due).

12,957
2,043


15,000
"
Y MachinesLtd. …………………Dr.
To Bank
(Being the amount paid in first instalment)

15,000

15,000
"
Depreciation A/c …………………Dr.
To Machinery A/c
(Being the depreciation charged)

5,585

5,585
"
Profit & Loss A/c …………………Dr.
To Interest A/c
ToDepreciation A/c
(Being the amount transferred)

7,628


2,043
5,585
2007
March 31
Machinery A/c ……………………………………...Dr.
Interest A/c ....................Dr.
To Y Machine Ltd.
(Being the second instalment due).

13,605
1,395


15,000
"
Y Machines Ltd. …………………Dr.
To Bank
(Being the amount paid in second instalment)

15,000

15,000
"
Depreciation A/c …………………Dr.
To Machinery A/c
(Being the depreciation charged)

5,027

5,027
"
Profit & Loss A/c …………………Dr.
To Interest A/c
ToDepreciation A/c
(Being the amount transferred)

6,422

1,395
5,027
2008
March 31
Machinery A/c ……………………………………...Dr.
Interest A/c ....................Dr.
To Y Machine Ltd.
(Being the third instalment due).

14,288
712


15,000
"
Y Machines Ltd. …………………Dr.
To Bank
(Being the amount paid in third instalment)

15,000

15,000
"
Depreciation A/c …………………Dr.
To Machinery A/c
(Being the depreciation charged)

4,524

4,524
"
Profit & Loss A/c …………………Dr.
To Interest A/c
To Depreciation A/c
(Being the amount transferred)

5,236

712
4,524

Note1:Interest has been calculated in the manner already explained in workedout example-1.
Description: http://WikiEducator.org/images/thumb/f/fc/SLMsections.png/65px-SLMsections.png
1.8 Calculation of Cash Price, if Cash Price is not given

Some times in a problem of hire-purchase, cash price of goods sold is not given. Only hire-purchase price is given under such situation first of all, cash price is to be calculated in order to find out the amount of interest included in each instalment. the cash price can be calculated under following two situations.
(a)By Annuity Method, if the annity value of Re. 1 is given:
Cash Price = (Annuity, Value of Re.1 x Amt. of one instalment) + down payment if, any.
Calculation of Cash Price by Annuity Method
Worked out Example-4
On 1st April,2005 a manufacturing company buys on Hire-purchase system a machinery for Rs. 60,000, payable by three equal annual instalments combining principal and interest, the rate of interest was 5% per annum. Calculate the amount of cash price and interest. The present value of an annuity of one rupee for three years at 5% interest is Rs. 2,72325.
Solution:
Calculation of Cash Price – The present value of an annuity of Re. 1 paid for 3 year @ 5% = Rs. 2,72325 Then the present value of Rs. 20,000 for 3 years = 2,72325 x 20,000 = Rs. 54,465 Cash Price Rs. 54,465

(b) By Arithmetic Method, if the annuity value of Re. 1 is not given:
? First take the last instalment and calculate interest included in that instalment. Interest: = (Amount of instalment x Rate of Int) / 100+Rate of Int.
Thereafter interest included in last but one instalment should be calculated. Interest = [(Amt. of last but one instalment + principal price included in the last instalment) x Rate of Interest] / 100+ Rate of Int.

  • ? Interest included in all proceeding instalment should be calculated in the same manner.
  • ? In the end, interest included in each instalment should be added. It should be remembered that down payment does not include any interest.
  • ? Finally cash price = Hire purchse price – Total interest included in various instalments.
Calculation of Cash Price by Arithmetic Method
Worked out Example-5
Mr. X purchased a machine on Hire-Purchase system on 1st April,2005. He paid Rs. 5,000 at spot and then three annual instalments of Rs. 5,000 each. The rate of interest was 5% per annum. Find out the amount of interest included in instalments and cash price of the machine.
Solution:

(1)First of all Interest included in the 3rd instalment is to be calculated.
Interest=(5000x5)/105=Rs. 238,Principal= 5000-238=4762
(2)Interest included in second instalment = [(5000+4762)x5]/105 = 465, Principal=4535
(3)Interest included in 1st instalment = [(5000+4762+4535)x5]/105 = 681,Principal=4319
Cash Price = 4762+4535+4319+down payment Rs.5000 = Rs.=18616
Total Interest=Rs20000-18616=1384. I Yr. rs.681, IIYr. Rs465, III Yr.Rs238
Note: Now you can make the interest table in the usual manner as explained in worked out example-1 and check your calculation of amount of interest.


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1.9 Calculation of Amount of Interest, if Rate of Interest is not given

Wherever, rate of interest is not given in the problem, again there can be two situations.
(a) When cash price and the amounts of instalments are given and the amount of each instalment is same. the following worked out example will make the calculation clear.
Worked out Example-6

(Calculation of Interest When Rate of Interest is not given) A machine was sold on hire-purchase system on 1st April,2005 Rs. 10,000 was paid at spot and rest was paid by four equal quarterly instalments of 22,000 each. The cash price of machine was Rs. 90,000. Find out the amount of interest included in each instalment.
Soluton:
Hire-purchase Price = 10,000 + (22,000 x 4) = Rs.98,000 Less: Cash Price Rs.90,000 Total Interest= Rs.8,000
The total Interest of Rs 8,000 is to be apportioned among the various instalments i.e. 4th, 3rd, 2nd and 1st instalment in the ratio of 1:2:3:4 (i.e. among 1st, 2nd, 3rd and 4th instalment in the ratio of 4:3:2:1)
(1)Share of 1st instalment in the Interest= 8,000x4/10 = Rs.3,200
(2)Share of 2nd instalment in the Interest= 8,000x3/10 = Rs.2,400
(3)Share of 3rd instalment in the interest= 8,000x2/10 = Rs.1,600
(4)Share of 2nd instalment in the interest= 8,000x1/10 = Rs. 800




(b) When cash price and amounts of instalments are given but the amount of each instalment is not equal: The following worked out example will clear the doubts.
Rate of Interest not known and Instalments of different amounts
Worked out Example-7
Cash price of a machine is Rs. 37,400 on 1st January,2003. Its hire-purchase price is Rs. 50,000. This hire-purchase price is paid in five annual instalments in the following manner: Rs. 15,000 at the end of the first year Rs. 12,000 at the end of second year; Rs. 10,000 at the end of third year, Rs. 8,000 at the end of fourth year, Rs. 5,000 at the end of fifth year. Calculate interest and cash price included in each instalment.


Solution:
Calculation of Interest Included in each Instalment
Total Interest= Hire-purchase price-Cash Price
Total Interest=Rs.50,000-37,400=12600
Total Interest of Rs12,600 is to be apportioned among the five instalments in the following manner:

Instalment No
Unpaid Amount(Rs.)
Calculation of Int.(Rs.)
First
50000
(12600x50000)/126000=5000
Second
50000-15000=35000
(12600x35000)/126000=3500
Third
35000-12000=23000
(12600x23000)/126000=2300
Fourth
23000-10000=13000
(12600x13000)/126000=1300
Fifth
13000-8000=5000
(12600x5000)/126000=500
Total
126000

Calculation of Cash Price included in each instalment
Instalment No.
Instalment(Rs.)
Interest(Rs.)
Cash Price(Rs.)
First
15000
5000
10000
Second
12000
3500
8500
Third
10000
2300
7700
Fourth
8000
1300
6700
Fifth
5000
500
4500
Total
50000
12600
37400








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Let's Sum Up


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Glossary





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Practice Test

1.11 Home Assignments:
Exercise-1:
AB Transport Company purchased a Truck from XY Automobiles Ltd. on Ist January,2001 on hire-purchase system. The cash price of the truck was Rs. 3,20,000 which was payable as under:

On 01-01-2001 Rs.1,00,000
On 31-12-2001 RS.80,000
On 31-12-2002 RS.80,000
On 31-12-2003 RS.82,478
XY Automobiles Ltd. charged interest @ 5% per annum on the unpaid amount. The purchasing company decided to write off depreciation @ 20% of the cost price each year. You are required to give the necessary journal entries in the books of both the parties for three years. Also show the calculation of interest, depreciation and the instalment.

Exercise-2 On Ist April,2001 Modern Traders Ltd. took delivery of one Truck from GE Motors Ltd. on Hire-Purchase Agreement, payable in three equal instalments of Rs. 60,000 each on 31st March,2002, 2003, 2004. The cash value of the Truck on delivery was Rs. 1,63,400. Vendor charges interest at 5 per cent per annum on the yearly balances. The purchaser wrote off depreciation @ 25 per cent on the diminishing value method for each year. Pass the necessary Journal entries to record the above transactions in the books of both the parties.

Exercise-3 A machinery is taken under the Hire-Purchase System for Rs. 2,500 to be paid as follows:
On delivery Rs. 400; at the end of first year Rs. 600; at the end of second year Rs.400; at the end of third year Rs. 1,100. Interest included in Rs. 2,500 being charged on the cash value at 10% per annum. Pass Journal entries in the books of hire-purchaser writing off depreciation @ 5% per annum on Diminishing Balance Method. Also give necessary accounts in the ledger of hire-purchaser.
Exercise-4 On Ist January,2001 Moti Ltd. purchased on Hire-Purchase System from Hire-Vendor some machinery for Rs. 25,500 payable in three equal instalments combining principal and interest, the latter being a normal rate of 5% per annum.
Calculate the amount of annual instalment, and show the Journal entries and necessary ledger accounts in the books of Moti Ltd. for three years. The present value of Annuity of Rupees one for three years at 5% interest is 2.72325.











(i) Chapter on Hire-puchase System in the Text Book “Advanced Accountancy” Volume I by R. L. Gupta and M Radhaswamy published by Sultan Chand & Co. New Delhi ( ISBN 81-8054-110-X )
(ii) Chapter on Hire-purchase System in the Text Book “Advanced Accountancy” by S. N. Maheshwari and S. K. Maheshari published by Vikas Publishing House New Delhi



 


Please help me with hire purchase maths problem?
i have this question which i have been looking over and over again but i cant solve it
the question is:

A bicycle has a marked price of $300. It can be bought through hire-purchase with a deposit of $60 and 10% interest on the outstanding balance, to be paid in 10 monthly installments
calculate
a) the amount of each monthy instalment
b) the total cost of buying the bicycle by hire purchase
Best Answer - Chosen by Asker
Total price = $300.

Deposit $60.

So; $300 - $60 = $240 left to pay.

10% interest on $240 = 0.1 * $240 = $24. So that's $24 interest.

Now; $240 + $24 = $264 to pay over 10 months.

(a) Monthly Instalments is $26.40 per month.
(b) Total cost of the bicycle is $300 +





















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Geometric Sequences
and Series

Topic Index | Algebra2/Trig Index | Regents Exam Prep Center

A sequence
is an ordered list of numbers. 
The sum of the terms of a sequence is called a series.
While some sequences are simply random values,
other sequences have a definite pattern that is used to arrive at the sequence's terms.
Two such sequences are the arithmetic and geometric sequences.  Let's investigate the geometric sequence.
Geometric Sequences
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MULTIPLY
If a sequence of values follows a pattern of multiplying a fixed amount (not zero) times each term to arrive at the following term, it is referred to as a  geometric sequence.   The number multiplied each time is constant (always the same).
     The fixed amount multiplied is called the common ratio, r, referring to the fact that the ratio (fraction) of the second term to the first term yields this common multiple.  To find the common ratio, divide the second term by the first term.
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/geometricgraph.gif
Notice the non-linear nature of the scatter plot of the terms of a geometric sequence.  The domain consists of the counting numbers 1, 2, 3, 4, ... and the range consists of the terms of the sequence.  While the x value increases by a constant value of one, the y value increases by multiples of two (for this graph).      
Examples:
Geometric Sequence
Common Ratio, r
5, 10, 20, 40, ...
r = 2
multiply each term by 2 to arrive at the next term
or...divide a2 by a1 to find the common ratio, 2.
-11, 22, -44, 88, ...
r = -2
multiply each term by -2 to arrive at the next term
.or...divide a2 by a1 to find the common ratio, -2.
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG9.gif
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG10.gif
multiply each term by 2/3 to arrive at the next term or...divide a2 by a1 to find the common ratio, 2/3.
Formulas used with geometric sequences and geometric series:
To find any term
of a geometric sequence:

Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG11.gif
where a1 is the first term of the sequence,
r is the common ratio, n is the number of the term to find.
Note:  a1 is often simply referred to as a.
To find the sum of a certain number of terms of a geometric sequence:
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG12.gif
where Sn is the sum of n terms (nth partial sum),
 a1 is the first term,  r is the common ration.
Examples:
Question
Answer
1.  Find the common ratio for the sequence
                   Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq10.gif
1.  The common ratio, r, can be found by dividing the second term by the first term, which in this problem yields -1/2.  Checking shows that multiplying each entry by -1/2 yields the next entry.
2.  Find the common ratio for the sequence given by the formula
                        Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq11.gif
2.  The formula indicates that 3 is the common ratio by its position in the formula.  A listing of the terms will also show what is happening in the sequence (start with n = 1).
                           5, 15, 45, 135, ...
The list also shows the common ratio to be 3.
3.  Find the 7th term of the sequence
                         2, 6, 18, 54, ...
3. n = 7;  a1 = 2, r = 3
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq1.gif
The seventh term is 1458.
4.  Find the 11th term of the sequence
                        Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG14.gif
4.  n = 11;  a1 = 1, r = -1/2
 Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG15.gif
5.  Find  a8 for the sequence
                   0.5, 3.5, 24.5, 171.5, ...
5.  n = 8;  a1 = 0.5,  r = 7

Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq9.gif
6.  Evaluate using a formula:
                             
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG16.gif
6.  Examine the summation
 
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG17.gif
This is a geometric series with a common ratio of 3.
n = 5;  a1 = 3, r = 3
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG18.gif
7.  Find the sum of the first 8 terms of the
     sequence
                     -5, 15, -45, 135, ...


 
7.  The word "sum" indicates a need for the sum formula.
n
= 8;  a1 = -5, r= -3
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithG19.gif
8.  The third term of a geometric sequence is 3 and the sixth term is 1/9.  Find the first term.
8. Think of the sequence as "starting with" 3, until you find the common ratio.
                Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq8.gif
For this modified sequence:  a1 = 3,  a4 = 1/9,
n = 4
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq24.gif
Now, work backward multiplying by 3 (or dividing by 1/3) to find the actual first term.
a1 = 27
9.  A ball is dropped from a height of 8 feet.  The ball bounces to 80% of its previous height with each bounce.  How high (to the nearest tenth of a foot) does the ball bounce on the fifth bounce?
                                                                  
                                              
9. Set up a model drawing for each "bounce".
                6.4, 5.12, ___, ___, ___ 
The common ratio is 0.8.
Description: http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq25.gif
Answer:  2.6 feet
 
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Check out how to use your TI-83+/84+ graphing calculator with sequences and series. Click here.

 

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ARITHMETIC PROGRESSSION 


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Arithmetic and Geometric Sequences (page 3 of 5)

The two simplest sequences to work with are arithmetic and geometric sequences. An arithmetic sequence goes from one term to the next by always adding (or subtracting) the same value. For instance, 2, 5, 8, 11, 14,... and 7, 3, –1, –5,... are arithmetic, since you add 3 and subtract 4, respectively, at each step. A geometric sequence goes from one term to the next by always multiplying (or dividing) by the same value. So 1, 2, 4, 8, 16,... and 81, 27, 9, 3, 1, 1/3,... are geometric, since you multiply by 2 and divide by 3, respectively, at each step.
The number added (or subtracted) at each stage of an arithmetic sequence is called the "common difference" d, because if you subtract (find the difference of) successive terms, you'll always get this common value. The number multiplied (or divided) at each stage of a geometric sequence is called the "common ratio" r, because if you divide (find the ratio of) successive terms, you'll always get this common value. Copyright © Elizabeth Stapel 2006-2011 All Rights Reserved
  • Find the common difference and the next term of the following sequence:
3, 11, 19, 27, 35,...
To find the common difference, I have to subtract a pair of terms. It doesn't matter which pair I pick, as long as they're right next to each other:
11 – 3 = 8
19 – 11 = 8
27 – 19 = 8
35 – 27 = 8
The difference is always 8, so d = 8. Then the next term is 35 + 8 = 43.
  • Find the common ratio and the seventh term of the following sequence:

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2/9, 2/3, 2, 6, 18,...
To find the common ratio, I have to divide a pair of terms. It doesn't matter which pair I pick, as long as they're right next to each other:
Description: (2/3)/(2/9) = 3, 2/(2/3) = 3, 6/2 = 3, 18/6 = 3
The ratio is always 3, so r = 3. Then the sixth term is (18)(3) = 54 and the seventh term is (54)(3) = 162.

Since arithmetic and geometric sequences are so nice and regular, they have formulas.
For arithmetic sequences, the common difference is d, and the first term a1 is often referred to simply as "a". Since you get the next term by adding the common difference, the value of a2 is just a + d. The third term is a3 = (a + d) + d = a + 2d. The fourth term is a4 = (a + 2d) + d = a + 3d. Following this pattern, the n-th term an will have the form an = a + (n – 1)d.
For geometric sequences, the common ratio is r, and the first term a1 is often referred to simply as "a". Since you get the next term by multiplying by the common ratio, the value of a2 is just ar. The third term is a3 = r(ar) = ar2. The fourth term is a4 = r(ar2) = ar3. Following this pattern, the n-th term an will have the form an = ar(n – 1).
  • Find the tenth term and the n-th term of the following sequence:
1/2, 1, 2, 4, 8,...
The differences don't match: 2 – 1 = 1, but 4 – 2 = 2. So this isn't an arithmetic sequence. On the other hand, the ratios are the same: 2 ÷ 1 = 2, 4 ÷ 2 = 2, 8 ÷ 4 = 2. So this is a geometric sequence with common ratio r = 2 and a = 1/2. To find the tenth and n-th terms, I can just plug into the formula an = ar(n – 1):
an = (1/2) 2n–1
a
10 = (1/2) 210–1 = (1/2) 29 = (1/2)(512) = 256
  • Find the n-th term and the first three terms of the arithmetic sequence having a6 = 5 and d = 3/2.
The n-th term of an arithmetic sequence is of the form an = a + (n – 1)d. In this case, that formula gives me a6 = a + (6 – 1)(3/2) = 5. Solving this formula for the value of the first term of the sequence, I get a = –5/2. Then:
a1 = –5/2, a2 = –5/2 + 3/2 = –1, a3 = –1 + 3/2 = 1/2,
and
an = –5/2 + (n – 1)(3/2)
  • Find the n-th term and the first three terms of the arithmetic sequence having a4 = 93 and a8 = 65.
Since a4 and a8 are four places apart, then I know from the definition of an arithmetic sequence that a8 = a4 + 4d. Using this, I can then solve for the common difference d:
65 = 93 + 4d
–28 = 4d

–7 = d
Also, I know that a4 = a + (4 – 1)d, so, using the value I just found for d, I can find the value of the first term a:
93 = a + 3(–7)
93 + 21 = a

114 = a
Once I have the value of the first term and the value of the common difference, I can plug-n-chug to find the values of the first three terms and the general form of the n-th term:
a1 = 114, a2 = 114 – 7 = 107, a3 = 107 – 7 = 100
an = 114 + (n – 1)(–7)
  • Find the n-th and the 26th terms of the geometric sequence with a5 = 5/4 and a12 = 160.
These two terms are 12 – 5 = 7 places apart, so, from the definition of a geometric sequence, I know that a12 = ( a5 )( r7 ). I can use this to solve for the value of the common ratio r:
160 = (5/4)(r7)
128 = r7

2 = r
Since a5 = ar4, then I can solve for the value of the first term a:
5/4 = a(24) = 16a
5/64 = a
Once I have the value of the first term and the value of the common ratio, I can plug each into the formulas, and find my answers:
an = (5/64)2(n – 1)
a26 = (5/64)(225) = 2 621 440
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Cite this article as:
Stapel, Elizabeth. "Arithmetic and Geometric Sequences." Purplemath. Available from
    http://www.purplemath.com/modules/series3.htm. Accessed 23 March 2013
 

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Metal Joining Techniques

Thank you for choosing flamencoengineers.blogspot.com. We always work hard to keep you, entertained, informed and updated. welcome Soldering, brazing, and welding are all methods of joining two or more pieces of metal and selected other materials. They are also methods used to fill gaps in metal parts. In welding, the two metals (or thermoplastic) must be similar . For example, copper cannot be welded to steel.  Welding uses high temperatures to melt and join two metal parts. A filler metal is often used as well.  When properly done, the finished weld is as strong as the surrounding metal.  But if the process is not carried out and the welder applies too much heat, it can change the metal’s properties and weaken the weld.  There are several different types of welding, including metal inert gas (MIG), arc,  electron beam,  laser, and  stir friction. Welding is also widely used to slice apart large metal structures by melting through them.

DIFFERENCE BETWEEN BLAZING , SOLDERING AND WELDING

Hello , i was from a workshop technology class in kenya and students COULDN'T differentiate BRazing , s oldering and WELDING , lET me save the situation SOLDER Joining two metals together by melting a third filler metal between them; the two metals being joined do not melt. The filler metal (solder) melts at around 840 °F (450 °C). BRAZE Mechanically this is the same process as soldering. It can be distinguished from soldering by temperature: in brazing the filler metal melts above 840 °F (450 °C). Because of the higher temperatures a brazed joint is stronger than a soldered joint. WELD In this process two metals are joined by melting them together. Of these three methods welding involves the hottest temperatures and welded joints are the strongest. Keep this in mind as you move from soldering to brazing to welding: as the heat required for melting increases the strength of the joint also increases. OVERALL, DETERMINING W